Question

Find the area of a trapezoid with bases that measure 9.2 CM and 7.7 cm and height 6.8 cm

Answer 1

`\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\ ---------\\ a=9.2\\ b=7.7\\ h=6.8 \end{cases}\implies A=\cfrac{6.8(9.2+7.7)}{2}`

Answer 2

The area of a trapezoid is 57.46 cm².

Explanation:

Formula

`Area\ of\ trapezoid = ((a + b))/(2)* h`

Where a, b are the two parallel bases of the trapezoid.

h is the height of the trapezoid.

As given

Trapezoid with bases that measure 9.2 cm and 7.7 cm and height 6.8 cm.

Put in the formula

`Area\ of\ trapezoid = ((9.2 + 7.7))/(2)* 6.8`

`Area\ of\ trapezoid = (16.9)/(2)* 6.8`

`Area\ of\ trapezoid = 8.45* 6.8`

Area of trapezoid = 57.46 cm²

Therefore the area of a trapezoid is 57.46 cm².