Solve for z. 3z + 1 = 4z + 19 z =

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asked Feb 3, 2019 180k views

2 Answers

Urobo · Answer 1 · 2019-02-08T21:54:47+0000

3z + 1 = 4z + 19

Subtract 4z from each side
3z + 1 − 4z = 4z + 19 − 4z
−z + 1 = 19

Subtract 1 from each side
−z + 1 − 1 = 19 − 1
−z = 18

Divide each side by -1
-z ÷ -1 = 18 ÷ -1
z = -18

Solve for z. 3z + 1 = 4z + 19 z =

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