Question

Plz help and explain :)))

Answer 1

Solve

`z^2-16z=-9`

Transpose -9 to the left to end up with the standard form of the quadratic equation:

`z^2-16z+9=0`
Since it does not appear to have rational roots, we proceed with the quadratic formula, where a=1, b=-16, c=9
and substitute in the quadratic formula:

`x=(-b\pm√(b^2-4ac))/(2a)`

`=(16\pm√((-16)^2-4*1*9))/(2)`

`=(16\pm√(256-36))/(2)`

`=8\pm√(55)`
i.e.
z=8+sqrt(55) or 8-sqrt(55)

Answer 2

Hello there!


See picture below...


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