Question

PLEASE PLEEEASE HELP ME IM BEGGING YOU WITH ALL MY HEART YOU GET 20 POINTS Solve for m:(m-4)^3 = (1/8)^-1

Answer 1

Your answer will be m=6. All you have to do is just take the square root of both sides and solve. Take the cubed root for each side of the equation t and set up an equation for m. then remove the perfect root factor, m-4 under the radical to solve for m. remove the negative exponent by writing (1/8)^-1 as 8. simplify the right side move all terms not containing m to the right side of the equation. since -4 does not contain  the variable to solve for, move it to the right side by adding 4 to both sides. then add 4+2 to get 6.

Answer 2

You can simplify the right side. Then, you need to take cube roots.
(m -4)³ = 1/(1/8) . . . rule of exponents
(m -4)³ = 8 . . . . . . .simplify
m -4 = ∛8 . . . . . . . take cube roots
m -4 = 2 . . . . . . . . use your calculator or knowledge to find ∛8
m = 6 . . . . . . . . . . add 4

The solution is m = 6.

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If you subtract the right side, you get a function of m that is zero when m has the right value. This graph shows that value is m = 6.