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Felicity recorded the number of laps she swam each month for 7 months.Her data is shown. 112,134,150,98,120,68,116 Which is the mean absolute deviation to the nearest whole numb…
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Felicity recorded the number of laps she swam each month for 7 months.Her data is shown. 112,134,150,98,120,68,116 Which is the mean absolute deviation to the nearest whole numb…
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Oct 18, 2019
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Felicity recorded the number of laps she swam each month for 7 months.Her data is shown.
112,134,150,98,120,68,116
Which is the mean absolute deviation to the nearest whole number of Felicity's lap data?
A.16
B.18
C.20
D.36
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The mean absolute deviation is 18.
We first find the mean. Find the sum of all of the data points and divide by 7, the number of data points:
(112+134+150+98+120+68+116)/7 = 798/7 = 114
Now we subtract the mean from each data point, find the absolute value of each one, find their sum, and divide by the number of data points:
(|112-114|+|134-114|+|150-114|+|98-114|+|120-114|+|68-114|+|116-114|)/7
= (2+20+36+16+6+46+2)/7 = 128/7 = 18
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Oct 23, 2019
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