Question

Two ramps are placed back to back as shown. What is the length of the ramp labeled x?

Answer 1

Explanation:

From the given figure, let ABC and ACD be the two ramps placed back to back.

Then, from ΔABC, we have

`(AC)/(AB)=sin13^[\circ}`

`(y)/(9)=sin13^(\circ)`

`(y)/(9)=0.224`

`y=9{*}0.224`

`y=2.02 ft`

Now, from ΔACD, we have

`(AC)/(AD)=sin7^(\circ)`

`(y)/(x)=0.121`

`x=(2.02)/(0.121)`

`x=16.7 feet`

Thus, the value of x is 16.7 feet.