Question

A student solved the equation sin2x/cos x = 2, 0 ≤ x ≤ pi, and got pi/2. What was the student's error?

Answer 1

Answer with Step-by-step explanation:

We are given a equation:

`(sin2x)/(cosx)=2`

Now, we will solve it

`(2sinxcosx)/(cosx)=2`

2sinx=2

sinx=1

all the possible values of x from 0 to π so that sinx=1 is

x=π/2

but, cos(π/2) is indeterminate