Question

11. A field is to be fertilized at a cost of $0.07 per square yard. The rectangular part of the field is 125 yards long and the diameter of each semicircle is 45 yards. Find the cost of fertilizing the field. Use 3.14 for π.

Answer 1

This might help with the problem

Answer 2

The cost of fertilizing the field is
`\$505.02`

Explanation:

we know that

The area of the figure is equal to the area of the rectangle plus the area of a complete circle (two semicircles)

Step 1

Find the area of the rectangle

The area of rectangle is equal to

`A=LW`

where

L is the length side of rectangle

w is the width side of the rectangle

In this problem we have

`L=125\ yd`

`W=D=45\ yd`

substitute

`A=125*45=5,625\ yd^(2)`

Step 2

Find the area of the circle

The area of the circle is equal to

`A=\pi r^(2)`

where

r is the radius of the circle

In this problem we have

`r=45/2=22.5\ yd`

substitute

`A=(3.14)(22.5)^(2)=1,589.625\ yd^(2)`

Step 3

Find the area of the figure

Adds the area of rectangle and the area of the circle

`5,625\ yd^(2)+1,589.625\ yd^(2)=7,214.625\ yd^(2)`

Step 4

Find the cost

Multiply the total area by
`0.07 (\$)/(yd^(2) )`

so

`7,214.625*0.07=\$505.02`