asked 35.9k views
2 votes
Solve. 0 = x² + 10x + 16
Enter your answers in the boxes.
The solutions are___and___.

asked
User Belrog
by
7.8k points

2 Answers

5 votes
pretty sure the answers are
x₁ = -2
x₂ = -8
answered
User Kenney
by
7.8k points
6 votes

Answer:

The solutions are
-2 and
-8

Explanation:

we know that

The formula to solve a quadratic equation of the form
ax^(2) +bx+c=0 is equal to


x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}

in this problem we have


x^(2) +10x+16=0

so


a=1\\b=10\\c=16

substitute in the formula


x=\frac{-10(+/-)\sqrt{10^(2)-4(1)(16)}} {2(1)}


x=(-10(+/-)√(36))/(2)


x=(-10(+/-)6)/(2)


x=(-10(+)6)/(2)=-2


x=(-10(-)6)/(2)=-8

The solutions are
-2 and
-8

answered
User Mariocatch
by
8.0k points

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