Question

Calculate the temperature of 5.85 mol N2 gas in 12.0 L steel bottle under the 10.0 atm of pressure.

Answer 1

Hello!

To calculate the temperature of 5,85 moles of N₂ gas in a 12,0 L steel bottle under 10,00 atm of pressure we need to use the Ideal Gas Law. This law relates the pressure and volume of a gas with its temperature and number of moles. The calculations for this exercise are shown below:


`P*V=n*R*T \\ \\ T= (P*V)/(n*R) \\ \\ T= ((10atm)*(12,0L))/((5,85 moles)(0,082 ( atm*L)/(mol*K)))= 250,16 K`

Now we convert this temperature to °C


`T( ^\circ C)=T(K)-273,15)=250,16-273,15=-22,99^\circ C`

So, the temperature of 5,85 moles of N₂ gas in a 12,0 L steel bottle under 10,00 atm of pressure is -22,99 °C

Have a nice day!