Question

consider the following equation. -2m(m+n-4)+5(-2m+2n)+n(m+4n-5) which of the following is an equivalent expression

Answer 1

The equivalent expression would be

-2m²-mn-2m+5n+4n².

We use the distributive property to multiply each piece of the expression first:

-2m*m+(-2m)*n-(-2m)*4+5(-2m)+5(2n)+n(m)+n(4n)-n(5)
= -2m²-2mn+8m-10m+10n+mn+4n²-5n

Combining like terms gives us:
-2m²-mn-2m+5n+4n²

Answer 2

the answer is -2m^2+4n^2-mn-2m+5