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In triangle ABC, AB=90 in., BC=80 in., and angle B measures 50 degrees. What is the approximate perimeter of the triangle?

In triangle ABC, AB=90 in., BC=80 in., and angle B measures 50 degrees. What is the approximate perimeter of the triangle?
asked 85.9k views
4 votes
in triangle ABC, AB=90 in., BC=80 in., and angle B measures 50 degrees. What is the approximate perimeter of the triangle?

asked
User Rishav Kumar
by
8.6k points

2 Answers

6 votes

Answer:

A. 242.4

Explanation:

edge 2020

answered
User Andrew Luo
by
7.9k points
0 votes
we know that

the Law of Cosines established:
AC² = AB² + BC² - 2·AB·BC·cos(b)
Therefore
AC = √(90² + 80² - 2·90·80·cos(50)
=√5243.86
= 72.4 in

Now you can sum up all the sides in order to find the perimeter:
AB + BC + AC = 90 + 80 + 72.4 = 242.4 in

the answer is
242.4 in
answered
User Edo
by
8.6k points
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