Question

I need help I been stuck on this assignment for 2 weeks because of that question.

Answer 1

A.
`-2√(2\pi )`

Explanation:

`f(x)=sin(x^(2)+\pi )`

`f^(')(x)=cos(x^(2) +\pi ) 2x`

`f^(')(√(2\pi ) )=cos(2\pi +\pi )2√(2\pi )`

`f^(') (√(2\pi ) )=-1 (2√(2\pi ) )`