asked 231k views
1 vote
What is the largest digit N for which 2345N is divisible by 6?

1 Answer

5 votes
Your answer would be N = 4
for a number to be divisible by 6, it must also be divisible by 2 and 3.
For a number to be divisible by 2, it must end in an even number: 0,2,4,6, or 8
For a number to be divisible by 3, the sum of the digits needs to be divisible by 3.

Considering 2345N, and knowing N has to be either 0,2,4,6, or 8 in such a way that when added to the other numbers we get a value divisible by 3 you can see that N must be equal to 4.. 2+3+4+5+4=18 and 18 is divisible by 3
answered
User Michael Broschat
by
7.8k points

Related questions

asked Oct 28, 2019 130k views
Selfagency asked Oct 28, 2019
by Selfagency
7.7k points
1 answer
4 votes
130k views
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.