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If f(x) =2x^2-2-10 what is the value of f(1) to the nearest tenth of necessary

If f(x) =2x^2-2-10 what is the value of f(1) to the nearest tenth of necessary
asked 53.3k views
3 votes
If f(x) =2x^2-2-10 what is the value of f(1) to the nearest tenth of necessary

asked
User Ankita Dobariya
by
8.1k points

1 Answer

3 votes
Wherever you see an x in the equation, simply sub in 1.

f(1) = 2(1)² - 2 - 10
= 2 - 2 - 10
= -10

Therefore, the answer is -10.


answered
User Joe Barbour
by
8.1k points
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