Question

Solve x^2+20x+100=50

Answer 1

`Factoring x^2+20x+50 \\ \\ x^2 + 20x + 50 = 0 \\ \\ we \ the \ find \ the \ vertex \ of \ y = x^2+20x+50 \\ \\ Since \ a \ square \ root \ has \ two \ values, \ one \\ positive \ and \ the \ other \ negative. \\ \\ x^2 + 20x + 50 = 0 \\has \ (2) \ solutions \\ x = -10 (+) \sqrt 50... \\ or... \\ x = -10 (-) \sqrt 50 \\ \\`

Sense the solution would then equal 100, we would then start switching.

10= 100

5= 50.


`\left[\begin{array}{ccc}100/5=20\end{array}\right]`

In this case, 20 would equal 2.

Your answer would then be the last option.