Question

Identify the oblique asymptote of f(x) = quantity 3 x squared plus 2x minus 5 over quantity x minus 4.

y = 0
y = 3x − 10
y = 3x + 14
No oblique asymptote

Answer 1

hello here is a solution : 

Answer 2

C is correct. y=3x+14

Explanation:

`f(x)=(3x^2+2x-5)/(x-4)`

We need to find oblique asymtotes of f(x).

Oblique asymtotes form when degree of numerator is greater than denominator.

First we find the degree of numerator and denominator for f(x)

Degree of f(x) at numerator = 2

Degree of f(x) at denominator = 1

So, one oblique asymtote form.

First we divide
`3x^2+2x-5` by
`x-4`

Quoetient of the above division would be oblique asymtote.

`(3x^2+2x-5)/(x-4)=3x+14+(51)/(x-4)`

So, oblique asymtote would be y=3x+14

C is correct option.