Question

Suppose x has a normal distribution with mean μ = 45 and standard deviation σ = 9. describe the distribution of x values for sample size n = 4. (round σx to two decimal places.) μx = σx =

Answer 1

The standard deviation of a particular sample is equal to the standard deviation divided by the square root of the sample size. That is,
`\sigma_x=(\sigma)/(\sqrt n)`
The mean of a particular sample is equal to the mean of the set the sample was taken from. That is,

`\mu_x=\mu`

`\text{In your case, }\sigma_x=(9)/(\sqrt4)=\frac92\text{ and }\mu_x=45.`