Question

A strong monoprotic acid ionizes in water. If the [H3O+] concentration is 1.56 x 10-4 M, what else is true?

Answer 1

If,
[H⁺] = 1.56 × 10⁻⁴ M
Then,
pH = -log (1.56 × 10⁻⁴)

pH = 3.80
Also,
pH + pOH = 14
So,
pOH = 14- 3.80

pOH = 10.2

Taking Anti log of pOH,

[OH⁻] = 10⁻¹⁰°²

[OH⁻] = 6.30 × 10⁻¹¹

Result:
For [H⁺] = 1.56 × 10⁻⁴ other true statements are,

1) [OH⁻] = 6.30 × 10⁻¹¹

2) pH = 3.80

3) pOH = 10.2