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1 vote
Cos^(2)x=(cscxcosx)/(tanx+cotx)

1 Answer

3 votes

\cos^2 x = (\csc x \cos x)/(\tan x + \cot x)


\cos^2 x = (\csc x \cos x)/((\sin x)/(\cos x) + (\cos x)/(\sin x))


\cos^2 x = (\csc x \cos x)/((\sin x)/(\cos x) * (\sin x)/(\sin x) + (\cos x)/(\sin x) * (\cos x)/(\cos x))


\cos^2 x = (\csc x \cos x)/((\sin^2 x)/(\sin x \cos x) + (\cos^2 x)/(\sin x \cos x))


\cos^2 x = (\csc x \cos x)/((1)/(\sin x \cos x))


\cos^2 x = \csc x \cos x \sin x \cos x


\cos^2 x = (1)/(\sin x) \cos x \sin x \cos x


\cos^2 x = \cos^2 x
answered
User Ruslan  Ismagilov
by
8.4k points
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