asked 67.7k views
4 votes
Use the quadratic formula to solve 5x=6x^2-3, what are the values of x?

asked
User Lynell
by
8.2k points

1 Answer

5 votes
5x= 6x^2 -3
6x^2 -5x -3
a = 6
b = -5
c = -3

x = [-b +- sq root(b^2 -4ac)] / 2a
x = [--5 +-
sq root (25 -(4*6*-3)] / 12
x = [5 +- sq root (25 + 72)] / 12
x = [5 + sq root (97)] / 12
x = 5 +-
9.84886] / 12
x1 =
1.237405
x2 =
-0.404072



answered
User Vishnu Upadhyay
by
8.6k points

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