asked 128k views
3 votes
A field is to be fertilized at a cost of $0.07 per square yard. The rectangular part of the field is 125 yd long and the diameter of each semicircle is 40 yd. Find the cost of fertilizing the field.

1 Answer

5 votes

Answer:

The cost of fertilizing the field is
\$437.96

Explanation:

we know that

The area of the figure is equal to the area of the rectangle plus the area of a complete circle (two semicircles)

Step 1

Find the area of the rectangle

The area of rectangle is equal to


A=LW

where

L is the length side of rectangle

w is the width side of the rectangle

In this problem we have


L=125\ yd


W=D=40\ yd

substitute


A=125*40=5,000\ yd^(2)

Step 2

Find the area of the circle

The area of the circle is equal to


A=\pi r^(2)

where

r is the radius of the circle

In this problem we have


r=40/2=20\ yd

substitute


A=\pi (20)^(2)=1,256.64\ yd^(2)

Step 3

Find the area of the figure

Adds the area of rectangle and the area of the circle


5,000\ yd^(2)+1,256.64\ yd^(2)=6,256.64\ yd^(2)

Step 4

Find the cost

Multiply the total area by
0.07 (\$)/(yd^(2) )

so


6,256.64*0.07=\$437.96

A field is to be fertilized at a cost of $0.07 per square yard. The rectangular part-example-1
answered
User M To The K
by
7.3k points
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