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If the change in enthalpy is -5074.1 kj , how much work is done during the combustion?

If the change in enthalpy is -5074.1 kj , how much work is done during the combustion?
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If the change in enthalpy is -5074.1 kj , how much work is done during the combustion?

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User Wilber
by
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1 Answer

4 votes
Hence,
∆H = ∆U + W
=>
W = ∆H - ∆U
= -5074 kJ - (-5084.) kJ
= 10 kJ
answered
User Jbchichoko
by
8.1k points
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