What is (x-5)(x-3)=10 as a quadratic equation

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asked Oct 21, 2019 93.2k views

1 Answer

Paul Gestwicki · Answer 1 · 2019-10-28T07:58:54+0000

Use the FOIL method for (x - 5)(x-3)

FOIL = First, Outside, Inside, Last

x(x) = x²
x(-3) = -3x
-5(x) = -5x
-5(-3) = 15

x² - 3x - 5x + 15 = 0

simplify by combining like terms

x² - 3x - 5x + 15 = 0
x² - 8x + 15 = 0

x² - 8x + 15 = 0 is your answer

hope this helps

What is (x-5)(x-3)=10 as a quadratic equation

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