Question

Give the values of a, b, and c needed to write the equation's general form. 2/3(x - 4)(x + 5) = 1

Answer 1

Rearranging what you have you get


`(2)/(3)x^2+(2)/(3)x-(43)/(3)=0`, thus


`a=(2)/(3), b=(2)/(3), c=(43)/(3)`

Answer 2

The first step is to write this equation into general form. The general form of an equation is:

ax^2 + bx + c = 0

To make this equation to general form, you have to simplify the equation first.

2/3(x-4) (x+5) = 1

2/3 (x^2 + 5x – 4x – 20) = 1

2/3(x^2 + x -20) = 1

2/3x^2 + 2/3x – 40/3 = 1

2/3x^2 + 2/3x – 40/3 – 1 = 0

2/3x^2 +2/3x – 43/3 = 0

Therefore, a = 2/3 ; b = 2/3 ; c = -43/3