Question

I need help with these 4 questions on my math homework! I have some examples with it but I still don't know how to do them... (Solved)

Answer 1

Explanation:

For equation N°2

`-x-3 = 0\\`

Solving algebraically:

`-x + x -3 = x` (Sum x on both sides of the equation)

`-3 = x\\`

Resolving graphically:

x = -2 --------- - (- 2) -3 = -1 pto (-2, -1)

x = -4 ---------- - (- 4) -3 = 1 pt (-4.1)

x = -3 --------- - (- 3) -3 = 0 pt (-3.0) Solution

The graphic is shown in the attached image. The red dot in the graph represents the solution

For equation N° 4

`9x +3 = 0\\`

Solving algebraically:

`9x+3 -3 = -3` (Sum -3 on both sides of the equation)

`9x =-3`

`(9x)/(9)=(-3)/(9)` (divided by 9 on both sides of the equation)

`x =(-3)/(9)` (simplifies the fraction)

`x =(-1)/(3)`

Resolving graphically:

x = 1 --------- 9 (1) +3 = 12 pt (1.12)

x = -1 --------- 9 (-1) +3 = -6 pto (-1, -6)

x = -1 / 3 -------- 9 (-1/3) +3 = 1 pt (-1 / 3.0) Solution

The graphic is shown in the attached image. The red dot in the graph represents the solution

For equation N°. 6.

`4x + 11 = 4x-24\\`

Solving algebraically:

`4x -4x +11 = 4x -4x-24` (Sum -4x on both sides of the equation)

`11 = -24` The equation is not met, the x are eliminated, therefore, it has solution

For equation N°. 8

`-6x +3 = -6x + 5\\`

Solving algebraically:

`-6x + 6x +3 = -6x + 6x +5` (Sum 6x on both sides of the equation)

`3 = 5` The x are eliminated, 3 is not equal to 5, the equality is not met. The equation has no solution.