Question

What are the zeros of the quadratic function f(x) = 2x2 + 8x – 3? x = –2 – and x = –2 + x = –2 – and x = –2 + x = 2 – and x = 2 + x = 2 – and x = 2 +

Answer 1

The answer is A for anyone that doesn't understand the other answer.

Answer 2

The given quadratic function is:


`f(x)=2 x^(2) +8x-3`

The zeros of the quadratic functions also known as its roots can be found using the quadratic formula.

According to the quadratic formula:


`x= \frac{-b+- \sqrt{ b^(2)-4ac } }{2a}`
here,
b = coefficient of x-term
a = coefficient of x²-term
c = costant term

For given function:
a = 2
b = 8
c = - 3

Using these values in the formula, we get:


`x= (-8+- √(64-4(2)(-3)) )/(2(2)) \\ \\ x= (-8+- √(88) )/(4) \\ \\ x= (-8+-2 √(22))/(4) \\ \\ x= (-4+- √(22) )/(2) \\ \\ x= (-4+ √(22) )/(2), x= (-4- √(22) )/(2)`

Thus, these values of x are the zeros of the given quadratic function f(x)=2x²+8x-3