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Factor completely. 4x^2 - 36 ( 2x + 6 ) ( 2x - 6) (2x + 18) ( 2x - 18) ( 4x + 4) (x - 9) ( 4x + 16) ( 4x -16) I don't know

Factor completely. 4x^2 - 36 ( 2x + 6 ) ( 2x - 6) (2x + 18) ( 2x - 18) ( 4x + 4) (x - 9) ( 4x + 16) ( 4x -16) I don't know
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1 vote
Factor completely. 4x^2 - 36

( 2x + 6 ) ( 2x - 6)
(2x + 18) ( 2x - 18)
( 4x + 4) (x - 9)
( 4x + 16) ( 4x -16)
I don't know

asked
User Morgan Courbet
by
8.6k points

1 Answer

1 vote
The answer should be ( 2x + 6) (2x - 6) By proving through expansion:
Factor completely. 4x^2 - 36 ( 2x + 6 ) ( 2x - 6) (2x + 18) ( 2x - 18) ( 4x + 4) (x-example-1
answered
User Heinob
by
7.7k points
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