Question

Work out the equation of the line which has a gradient of 3 and passes through the point (-1,3)

Answer 1

`\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ &&(~ -1 &,& 3~) \end{array} \\\\\\ % slope = m slope = m\implies 3 \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-3=3[x-(-1)] \\\\\\ y-3=3(x+1)\implies y-3=3x+3\implies y=3x+6`

Answer 2

Answer: y=3x+6

Step-by-step explanation: use y=mx+c