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F(x) = (x − 3)(x + 3)[x − (2 − i)][x − (2 + i)] The function has real roots and imaginary roots.
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F(x) = (x − 3)(x + 3)[x − (2 − i)][x − (2 + i)] The function has real roots and imaginary roots.
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Sep 15, 2019
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f(x) = (x − 3)(x + 3)[x − (2 − i)][x − (2 + i)] The function has real roots and imaginary roots.
Mathematics
high-school
William T Froggard
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William T Froggard
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The real roots are 3 and -3.
Imaginary roots:-
x - (2 - i) = 0
x = 2 -i is one imaginary root and the other is 2 + i
Rozsazoltan
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Sep 17, 2019
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Rozsazoltan
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Answer:
The function has
2 real roots and
2 imaginary roots.
Amit Gujarathi
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Sep 20, 2019
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Amit Gujarathi
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