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A plumbing contractor receives proceeds of $4,713.54 on a 12.5% simple discount note with a face value of $5,000. Find the time of the note in days. (Assume a 360-day year.) Do …
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A plumbing contractor receives proceeds of $4,713.54 on a 12.5% simple discount note with a face value of $5,000. Find the time of the note in days. (Assume a 360-day year.) Do …
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Aug 5, 2019
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A plumbing contractor receives proceeds of $4,713.54 on a 12.5% simple discount note with a face value of $5,000. Find the time of the note in days. (Assume a 360-day year.) Do not round intermediate calculations!
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I = Prt
t = I/(Pr)
.. = (5000 -4713.54)/(5000*0.125)
.. = 165/360
The time period of the note is 165 days.
AJPatel
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Aug 11, 2019
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