Question

What is the missing constant term in the perfect square that starts with x²+6x?

Answer 1

the missing term is 9

Answer 2

The expression given to us is: x²+6x

Now, we know that the second term is twice the square root of the first and the last terms. Let us call the last term as
`y^2`. Thus our given expression will become:

`x^2+6x+y^2`.

Now, since the middle term is 6x and since we know that the second term is twice the square root of the first and the last terms, therefore,

`6x=2* √(x^2) * √(y^2)`

`6x=2* x* y`

`\therefore y=3` (By dividing both sides by 2x)

Therefore, the missing term is 3.