Question

What is the sum of the geometric series rounded to the nearest whole number?

A.4
B.0
C.2
D.3

Answer 1

Option A.
`4`

Explanation:

we know that

The sum of a geometric series is equal to

`Sum=a((1-r^(n))/(1-r))`

where

a is the first term

r is the common ratio

n is the number of terms

In this problem we have

`a=2,r=0.5,n=16`

substitute the values

`Sum=2((1-0.5^(16))/(1-0.5))=4`