asked 202k views
0 votes
A rectangular deck

is 12 ft by 14 ft. When the length and width are increased by the same amount very becomes 280 squares ft. By how much were the dimensions increased ?

asked
User Montuno
by
7.4k points

2 Answers

1 vote
Original length: 14 ft. New length x + 14.
Original width: 12 ft. New width x + 12.

New area:


A = LW or
LW = A


(x + 14)(x + 12) = 280


x^2 + 14x + 12x + 168 = 280


x^2 + 26x - 112 = 0


x = (-b \pm √(b^2 - 4ac))/(2a)


x = (-26 \pm √(26^2 - 4(1)(-112)))/(2(1))


x = (-26 \pm √(676 + 448))/(2)


x = (-26 \pm √(1124))/(2)


x = (-26 \pm 2√(281))/(2)


x = -13 \pm √(281)


x \approx -29.76 or
x \approx 3.76

We discard the negative answer.

Answer:

Exact:

(-13 + √(281))~ ft

Approximate:

3.76 ~ft
answered
User Portman
by
8.2k points
4 votes
Both dimensions were increased by 127.

The other response seems more complex so probably ignore mine. I probably misinterpreted the question.

answered
User Mir Mahfuz
by
8.5k points

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