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1 vote
Urgent help please. 30 points

The final game is altered:

Bag One has 5 red balls and 9 blue balls.
Bag Two has 6 red balls and 7 blue balls.

Complete the tree diagram:

Urgent help please. 30 points The final game is altered: Bag One has 5 red balls and-example-1
asked
User VelNaga
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8.8k points

2 Answers

6 votes
I believe it goes 6 7 5 9
answered
User Egor Rogov
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8.1k points
1 vote

Answer:

A. 7/13 B. 9 C. 13 D. 7/13 E. 5/14 F. 6/13 G. Red

Explanation:

First we take a ball from bag one, there are 14 balls, 5 red, 9 blue, then, there is 5/14 for red and 9/14 for blue.

Then we take a ball from the second bag and we have 13 balls: 7blue and 6 red, so the posibilities are 7/13 for blue and 6/13 for red.

As it doesn't says anything about mixing balls of both bags, it does not matter the result of the first bag for the probabilities in the second one.

answered
User SunnySun
by
8.6k points

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