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For y=4×+2x^2-x^3, show how to find the value of y when x=2

For y=4×+2x^2-x^3, show how to find the value of y when x=2
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For y=4×+2x^2-x^3, show how to find the value of y when x=2

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User Mttrb
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1 Answer

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just put two instead of x like y = 4.2+2.4(2 squared)-8(cubic 2) that gives y= 8+8-8= 8 then y equals 8
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User Mergenchik
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