asked 114k views
5 votes
Fill in the table and guess the value of the limit: \lim\limits_{x \to 3} f(x), where f(x)= \frac {x^3 - 27} {x^2 - 9}

1 Answer

6 votes
Try this option:

\lim_(x \to 3) (x^3-27)/(x^2-9) = \lim_(x \to 3) (x^2+3x+9)/(x+3)= (27)/(6)= (9)/(2)
answered
User Twogoods
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