asked 79.7k views
4 votes
What is the density of a mineral with a mass of 41.2 g and a volume of 8.2 cm3? 49.4 g/cm3 5.02 g/cm3 0.19 g/cm3 337.8 g/cm3

asked
User Meike
by
8.5k points

2 Answers

3 votes
i think the correct answer would be 5.02g cm3
answered
User Marquinio
by
8.3k points
5 votes

Answer:

Density of the mineral is equal to
5.02 (g)/(cm^(3) )

Step-by-step explanation:

The density of a substance is equal to mass of the substance divided by its volume.

Thus, the formula of density (d) is as follows


d = (M)/(V)

Where, M represent the mass of a substance

and V represents the volume of the same substance

Substituting the given values in above equation, we get -


d = (41.2)/(8.2) (g)/(cm^(3) ) \\d = 5.02 (g)/(cm^(3) ) \\

Hence, option B is correct

answered
User Ernd Enson
by
8.4k points
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