Question

A certain shade of blue has a frequency of 7.15 × 1014 hz. what is the energy of exactly one photon of this light?

Answer 1

The energy carried by a single photon of frequency f is given by:

`E=hf`
where
`h=6.6 \cdot 10^(-34) m^2 kg s^(-1)` is the Planck constant. In our problem, the frequency of the photon is
`f=7.15 \cdot 10^(14)Hz`, and by using these numbers we can find the energy of the photon:

`E=(6.6\cdot 10^(-34)m^2 kg s^(-1))(7.15 \cdot 10^(14)Hz)=4.7 \cdot 10^(-19)J`