Question

Two charged parallel plates are 0.25 meters away from each other. The field between the plates is 600 . What is the electric potential difference?

Answer 1

ΔV = 150 V

Step-by-step explanation:

Answer 2

I assume that "600" is
`600 V/m`.

The relationship between the intensity of the electric field E and the potential difference
`\Delta V` is given by

`\Delta V = Ed`
where d is the distance between the two points at which the potential difference is calculated.
Using
`E=600 V/m` and
`d=0.25 m`, we find

`\Delta V=Ed=(600 V/m)(0.25 m)=150 V`