asked 73.2k views
3 votes
A restaurant offers a "Create Your Own Pizza" menu option. There are 3 types of meat, 6 types of vegetables, and 3 kinds of cheese. Customers may choose one meat, one vegetable, and one cheese. You decide to have the chef choose the toppings randomly. What is the probability that the chef will make a pizza with chicken, banana peppers, and ricotta cheese?

asked
User SparkyNZ
by
7.6k points

1 Answer

3 votes
Multiply 3 times 6 times 3 to get the total number of choices.
Since there can only be one meat, one vegetable, and one cheese, the chances are 1/54.
answered
User Umer Farooq
by
7.8k points
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