Question

A man drops a ball off of a 7.2 m high cliff, what is the ball's velocity as it hits the ground?

(- 12m/s)
Proof llease

Answer 1

19.3 m/s

1. Step-by-step explanation:

Take down to be positive. Given:

Δy = 19 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (9.8 m/s²) (19 m)

v = 19.3 m/s

My camera quality is bad. Sorry..