Question

the area of a trapezoid is 72.8 square feet. the length of one of its bases is 7.4 feet and the length of its other base is 10.8 feet. what is the height of the trapezoid?

Answer 1

`\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}\quad \begin{cases} a,b=\stackrel{parallel~sides}{bases}\\ h=height\\ --------\\ A=72.8\\ a=7.4\\ b=10.8 \end{cases}\implies 72.8=\cfrac{h(7.4+10.8)}{2} \\\\\\ 72.8=\cfrac{18.2h}{2}\implies \cfrac{72.8\cdot 2}{18.2}=h`