asked 49.5k views
4 votes
If Z = 2(cos95 - isin95)
Find Z^2

asked
User Liane
by
7.7k points

1 Answer

5 votes
So we have:


\sf (2(cos(95\textdegree)- i sin(95\textdegree)))^2

Convert to radians:


\sf (2(cos((19)/(36)\pi)- i sin((19)/(36)\pi)))^2

Use the identity:
\sf cos(x)-isin(x)=e^(-ix)


\sf (2e^{-i(19)/(36)\pi})^2

Simplify:


\sf e^{-i(19)/(36)\pi}=\frac{1}{(-1)^{(19)/(36)}}


\sf (2*\frac{1}{(-1)^{(19)/(36)}})^2\rightarrow \boxed{\sf 4(-1)^{(17)/(18)}}
answered
User Otorrillas
by
8.2k points

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