Missing question:
a. C6H12O6
b. CH3OH
c. C12H22O11
d. NaOH.
Answer is: d. NaOH.
b(solution) = 0,1 m.
ΔT = Kf · b(solution) · i.Kf - the freezing point depression constant.
i - Van 't Hoff factor. Because dissociate on one cation and one anions, sodium hydroxide has i = 2, other molecules has covalent bonds (i = 1, do not dissociate on ions). Because molality and the freezing point depression constant are constant, greatest freezing point lowering is solution with highest Van 't Hoff factor.