Given: KLMN is a parallelogram, KA − angle bisector of ∠K LA − angle bisector of ∠L Prove: m∠KAL = 90°

Question

asked Jul 4, 2019 229k views

1 Answer

Rob Burke · Answer 1 · 2019-07-08T23:39:54+0000

Answer:

m∠NKL + m∠KLM = 180°

by reason

consecutive angles of parallelogram supplementary

Explanation:

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