Question

Help Needed

Let ​f(x)=x2+12x+32.​ What are the zeros of the function? Enter your answers in the boxes.

Answer 1

The zeros of this function is -4 and -8

Answer 2

Explanation:

The given equation is:

`f(x)=x^2+12x+32`

Simplifying the above expression, we have

`f(x)=x^2+4x+8x+32`

`f(x)=x(x+4)+8(x+4)`

`f(x)=(x+4)(x+8)`

Thus, zeroes of the given function will be:

`f(x)=0`

`(x+4)(x+8)=0`

`x=-4 and x=-8`

Therefore the zeroes of the given function are
`x=-4 and x=-8`.