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Solve the system by the substitution method. 4x+y=0 8x−2y=6

Solve the system by the substitution method. 4x+y=0 8x−2y=6
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Solve the system by the substitution method.
4x+y=0
8x−2y=6

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User Kecman
by
8.4k points

1 Answer

4 votes
4x+y=0 so y = -4x
substitute y = - 4x into 8x−2y=6
8x−2y=6
8x - 2(-4x) = 6
8x + 8x = 6
16x = 6
x = 3/8

y = -4(3/8) = - 3/2

answer
(3/8 , -3/2)
answered
User David Carrigan
by
8.8k points
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