asked 124k views
1 vote
What volume of a 2.5 M stock solution of acetic acid (HC2H3O2) is required to prepare

100.0 milliliters of a 0.50 M acetic acid solution?

Use the equation

Mconcentrated × Vconcentrated = Mdilute × Vdilute.

90points given to correct answer

2 Answers

3 votes

Answer:

20 milliliters

Step-by-step explanation:

I don't cap

4 votes

Answer is: volume is 20 mL.
c
₁(CH₃COOH) = 2,5 M.
c
₂(CH₃COOH) = 0,5 M.
V
₂(CH₃COOH) = 100 mL.
V
₁(CH₃COOH) = ?
c
₁(CH₃COOH) · V₁(CH₃COOH) = c₂(CH₃COOH) · V₂(CH₃COOH).
2,5 M · V
₁(CH₃COOH) = 0,5 M · 100 mL.
V
₁(CH₃COOH) = 0,5 M · 100 mL ÷ 2,5 M.
V
₁(CH₃COOH) = 20 mL ÷ 1000 mL/L =0,02 L.

answered
User Obecalp
by
7.6k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.