asked 221k views
5 votes
Which of the following equilibrium systems most favors the products? a) CI2(g) + 2NO2(g) 2NO2CI(g); Keq = 1.8 b) N2(g) + 3H2(g) 2NH3(g); Keq = 345 c) 2HCI2(g) H2(g) + CI2(g); Keq = 2.0 × 10-7 d) CI2(g) + 2NO(g) 2NOCI(g); Keq = 3.7 × 108

2 Answers

3 votes
CI2(g) + 2NO(g) 2NOCI(g); Keq = 3.7 × 10^8
answered
User Pavel Yakimenko
by
8.1k points
7 votes

Answer: The correct answer is Option d.

Step-by-step explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
K_(eq)

For a general chemical reaction:


aA+bB\rightarrow cC+dD

The expression for
K_(eq) is written as:


K_(eq)=([C]^c[D]^d)/([A]^a[B]^b)

There are 3 conditions:

  • When
    K_(eq)>1; the reaction is product favored.
  • When
    K_(eq)<1; the reaction is reactant favored.
  • When
    K_(eq)=1; the reaction is in equilibrium.

From the above expression, the equilibrium constant is directly dependent on product concentration. Thus, more is the concentration of product, more will be the equilibrium constant.

The highest values of
K_(eq) will favor the product more.

Hence, the correct answer is Option d.

answered
User Olivier Dulac
by
8.8k points
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